Improve language
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@ -112,8 +112,8 @@ Another way to calculate binomial coefficients is as follows:
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There are $n!$ permutations of $n$ elements.
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There are $n!$ permutations of $n$ elements.
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We go through all permutations and always
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We go through all permutations and always
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select the first $k$ elements of the permutation
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include the first $k$ elements of the permutation
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to the subset.
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in the subset.
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Since the order of the elements in the subset
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Since the order of the elements in the subset
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and outside the subset does not matter,
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and outside the subset does not matter,
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the result is divided by $k!$ and $(n-k)!$
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the result is divided by $k!$ and $(n-k)!$
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@ -124,10 +124,9 @@ For binomial coefficients,
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\[
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\[
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{n \choose k} = {n \choose n-k},
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{n \choose k} = {n \choose n-k},
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\]
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\]
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because we can either select $k$
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because we actually divide a set of $n$ elements into
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elements that belong to the subset
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two subsets: the first contains $k$ elements
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or $n-k$ elements that
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and the second contains $n-k$ elements.
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do not belong to the subset.
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The sum of binomial coefficients is
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The sum of binomial coefficients is
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\[
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\[
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