Fix 'weight' -> 'value' in Knapsack solution 2

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JulienC 2017-04-23 18:48:15 -04:00
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@ -683,7 +683,7 @@ using the following sequence:
denote the smallest possible total weight
when a subset of objects
$1 \ldots k$ is selected such
that the total weight is $u$.
that the total value is $u$.
The solution to the problem is the
largest value $u$
for which $0 \le u \le s$ and $f(n,u) \le x$