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Fix unsigned upper bound [closes #56]

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Antti H S Laaksonen 2017-11-19 23:12:57 +02:00
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chapter10.tex
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@ -77,7 +77,7 @@ of the bit representation, the number will overflow.
In a signed representation,
the next number after $2^{n-1}-1$ is $-2^{n-1}$,
and in an unsigned representation,
the next number after $2^{n-1}$ is $0$.
the next number after $2^n-1$ is $0$.
For example, consider the following code:
\begin{lstlisting}
int x = 2147483647