Fix typo
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@ -457,8 +457,8 @@ After this change, the time complexity is $O(n^2)$.
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Surprisingly, it is possible to solve the problem
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Surprisingly, it is possible to solve the problem
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in $O(n)$ time\footnote{In \cite{ben86}, this linear-time algorithm
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in $O(n)$ time\footnote{In \cite{ben86}, this linear-time algorithm
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is attributed to J. B. Kadene, and the algorithm is sometimes
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is attributed to J. B. Kadane, and the algorithm is sometimes
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called \index{Kadene's algorithm} \key{Kadene's algorithm}.}, which means
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called \index{Kadane's algorithm} \key{Kadane's algorithm}.}, which means
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that just one loop is enough.
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that just one loop is enough.
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The idea is to calculate, for each array position,
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The idea is to calculate, for each array position,
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the maximum sum of a subarray that ends at that position.
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the maximum sum of a subarray that ends at that position.
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@ -28,6 +28,6 @@ You can always send feedback on the book to
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\texttt{ahslaaks@cs.helsinki.fi}.
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\texttt{ahslaaks@cs.helsinki.fi}.
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\begin{flushright}
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\begin{flushright}
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Helsinki, June 2017 \\
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Helsinki, July 2017 \\
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Antti Laaksonen
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Antti Laaksonen
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\end{flushright}
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\end{flushright}
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