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Antti H S Laaksonen 2017-02-18 19:37:34 +02:00
parent 9da26930f3
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@ -52,9 +52,9 @@ This is a possible way to solve the problem,
but there is one pitfall:
how to divide the quadrilateral into triangles?
It turns out that sometimes we cannot just pick
two arbitrary vertices.
two arbitrary opposite vertices.
For example, in the following situation,
the division line lies outside the quadrilateral:
the division line is outside the quadrilateral:
\begin{center}
\begin{tikzpicture}[scale=0.45]
@ -135,7 +135,7 @@ as complex numbers, and the class also contains tools
that are useful in geometry.
In the following code, \texttt{C} is the type of
a coordinate, and \texttt{P} is the type of a point or vector.
a coordinate and \texttt{P} is the type of a point or vector.
In addition, the code defines the macros \texttt{X} and \texttt{Y}
that can be used to refer to x and y coordinates.
@ -284,7 +284,7 @@ of the result is $x_1 y_2 - x_2 y_1$.
\subsubsection{Point location}
The cross product can be used for testing
Cross products can be used for testing
whether a point is located on the left or right
side of a line.
Assume that the line goes through points