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Small fix

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Antti H S Laaksonen 2017-05-17 21:25:50 +03:00
parent b04892ed47
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chapter01.tex
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@ -594,7 +594,7 @@ using the formula
\[a + ak + ak^2 + \cdots + b = \frac{bk-a}{k-1}\] \[a + ak + ak^2 + \cdots + b = \frac{bk-a}{k-1}\]
where $a$ is the first number, where $a$ is the first number,
$b$ is the last number and the $b$ is the last number and the
ratio between consecutive numbers is $x$. ratio between consecutive numbers is $k$.
For example, For example,
\[3+6+12+24=\frac{24 \cdot 2 - 3}{2-1} = 45.\] \[3+6+12+24=\frac{24 \cdot 2 - 3}{2-1} = 45.\]