From dd4da8e2c03c275c318da210c7ddc7d7397b63f4 Mon Sep 17 00:00:00 2001
From: Yee-Ning Cheng <ycheng@tremorvideo.com>
Date: Fri, 28 Dec 2018 09:04:09 -0500
Subject: [PATCH] Fix minor typo

---
 chapter06.tex | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/chapter06.tex b/chapter06.tex
index 326d63c..8cc1f69 100644
--- a/chapter06.tex
+++ b/chapter06.tex
@@ -409,7 +409,7 @@ so the median is 2.
 The median is an optimal choice,
 because if $x$ is smaller than the median,
 the sum becomes smaller by increasing $x$,
-and if $x$ is larger then the median,
+and if $x$ is larger than the median,
 the sum becomes smaller by decreasing $x$.
 Hence, the optimal solution is that $x$
 is the median.