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Fix minor typo

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Yee-Ning Cheng 2018-12-28 09:04:09 -05:00
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chapter06.tex
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@ -409,7 +409,7 @@ so the median is 2.
The median is an optimal choice,
because if $x$ is smaller than the median,
the sum becomes smaller by increasing $x$,
and if $x$ is larger then the median,
and if $x$ is larger than the median,
the sum becomes smaller by decreasing $x$.
Hence, the optimal solution is that $x$
is the median.